integrate (x.e^x+1) (e^x+logx)^2 /x. dx
Answers
Answered by
4
Answer:
Putting xe
x
=t
(xe
x
+e
x
)dx=dt
∫logtdt
From by parts, we have
tlogt−t+C
xe
x
logxe
x
−xe
x
+C
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Answered by
1
Answer:
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