Math, asked by devarajrv761, 4 months ago

integrate (x.e^x+1) (e^x+logx)^2 /x. dx

Answers

Answered by AnushkaMate56

4

Answer:

Putting xe

x

=t

(xe

x

+e

x

)dx=dt

∫logtdt

From by parts, we have

tlogt−t+C

xe

x

logxe

x

−xe

x

+C

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Answered by sara6857

1

Answer:

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