integrate x³-1/x³+x dx
Answers
Given : (x³-1)/(x³+x) dx
To Find : Integrate
Solution:
(x³-1)/(x³+x)
Add and subtract x in numerator
= (x³ + x - x - 1) /(x³ + x)
= (x³ + x)/(x³ + x) - (x + 1)/(x³ + x)
= 1 - (x + 1)/x(x² + 1)
(x + 1)/x(x² + 1) = A/x + (Bx +C)/(x² + 1)
=> x + 1 = A(x² + 1) + Bx² + Cx
x = 0 => 1 = A
x = - 1
=> 0 = 2(1) + B - C => B - C = -2
x = 1
=> 2 = 2(1) + B + C => B + C = 0
=> B = - 1 , C = 1
(x + 1)/x(x² + 1) = 1/x + (-x +1)/(x² + 1)
(x³-1)/(x³+x) = 1 - ( 1/x + (-x +1)/(x² + 1) )
= 1 - 1/x + x/(x²+ 1) - 1/(x² + 1)
∫(x³-1)/(x³+x) dx
= ∫dx - ∫dx/x + ∫xdx/(x² + 1) - ∫dx/(x² + 1)
= ∫dx - ∫dx/x + (1/2)∫2xdx/(x² + 1) - ∫dx/(x² + 1)
= x - ln|x| + (1/2) ln|x² + 1| - tan⁻¹x + C
∫(x³-1)/(x³+x) dx = x - ln|x| + (1/2) ln|x² + 1| - tan⁻¹x + C
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Answer:
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