integrate xsin^-1x/√(1-x^2)
Answers
Answered by
3
First integrate by parts:
∫fg′=fg−∫f′g
f =arccos(x), g′ =x/√1−x^2
f′ =−1/√1−x2, g =−√1−x2
= −√1−x2arccos (x)−∫1 dx
Now solve: ∫1 dx, apply constant rule: =x
Plug in our solved integrals:
−√1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−x
Thus the answer is:
−√1−x2arccos(x)−x+C
Where C is any constant
HOPE IT HELPS YOU
MARK ME ON BRAINLIEST
∫fg′=fg−∫f′g
f =arccos(x), g′ =x/√1−x^2
f′ =−1/√1−x2, g =−√1−x2
= −√1−x2arccos (x)−∫1 dx
Now solve: ∫1 dx, apply constant rule: =x
Plug in our solved integrals:
−√1−x2arccos(x)−∫1dx =−√1−x2arccos(x)−x
Thus the answer is:
−√1−x2arccos(x)−x+C
Where C is any constant
HOPE IT HELPS YOU
MARK ME ON BRAINLIEST
1118roshani:
what is arccosx
Similar questions