Question

integrate1 (x2+1)2 dx​

Answer 1

Answer:

put x^2+1 = t

then 2x dx = dt

now dx = dt /2x

Integration of t dt/2x

now x=

$\sqrt{t - 1}$

so Integration of t/√t-1 dt

now rationalise √t-1

We get Integration of t(√t-1)/t-1 dt

Now solve it