Question

integration 1 + cot X by X + log sin x dx

Answer 1

Let x + logsinx = t

By differentiating w.r.to.x we get-

1+ cosx/sinx dx = dt

1 + cotx dx =dt

Now putting it in

I= £ 1+ cotx/x+ logsinx dx

I= £1+cotx/t dx

I= £ 1/t d

I= log t+ c

( since symbol of integration was not there i have used "£" instead of that. So dont get confused)