Question

integration 1 to e integration 1 to e integration 1 to e 1/xyz dx dy dz​

Answer 1

Answer:

$\int\limits^e_1 {\frac{1}{xyz} } \, dxdydz$

$= \int\limits^e_1 {\frac{1}{x} } \, dx \frac{1}{y} dy\frac{1}{z} dz$

= log(x)log(y)log(z) from limits 1 to e

= [log(e)]³ - 0

= [1]³

= 1

The answer is 1.

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