integration 1/x^3 DX
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Heyy!
Here's your answer
Step-by-step explanation:
We first need to recognize that
1/x^3
is equivalent to x^−3 .
Once we get that far, the problem becomes quite simple to solve.
Do be careful, however, as we are dealing with a negative exponent, so when we add one to the power as we take the anti-derivative, the magnitude of the power will decrease. This also means that our constant will have to be negative as well, since the x term in the integral is positive. Taking the anti-derivative, we get:
−1/2*x^−2+C
This is equivalent to −1/2x^2+C
As usual, you can check this answer by taking the derivative, which gives you
x^−3 .
Hope this helps you...
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