Math, asked by pkoti647598, 2 months ago

integration (2x-1/3√x)^2 dx=

Answers

Answered by pyalchaudhary123
0

Answer:

(2x-1/3√x)^2=4x^2-1/9x-4√x/3

int.(2x-1/3√x)^2= int. (4x^2-1/9x-4√x/3)

= 4x^3/3-(1/9)log x -8x^(3/2)/9

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