integration 4/x(x⁴-1)
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HELLO FRIEND,
HERE IS YOUR SOLUTION,
i the given question multiply x in numerator and denominator. Then you will get,
integration of 4x/[x^2(x^4-1)]
Now, put x^2= t
then on differentiate it you will get,
2x dx = dt
substitute these in given integration. You will get
integration of 2dt/[t(t^2-1)]
By using Integration by-parts you will get your Answer.
HERE IS YOUR SOLUTION,
i the given question multiply x in numerator and denominator. Then you will get,
integration of 4x/[x^2(x^4-1)]
Now, put x^2= t
then on differentiate it you will get,
2x dx = dt
substitute these in given integration. You will get
integration of 2dt/[t(t^2-1)]
By using Integration by-parts you will get your Answer.
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