Question

integration 6x+5/root6-2x^2+x
plz it's urgent​

Answer 1

Step-by-step explanation:

Let 6x + 5 = A (1 – 4x) + B

Equating the co-efficients of x; 6 = – 4 A ⇒ A = − 3/2

Equating the constants A + B = 5; B = 5 – A = 5 + (3/2) = 13/2

∫ (6x + 5) √(6 − 2x2 + x) dx = - (3/2)

∫ (1 - 4x) √(6 - 2x2 + x) dx + (13/2)

∫ √(6 - 2x2 + x) dx

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