Question

integration by substitution ,. 7/2-3x dx = ?

Answer 1

put 2-3x = t
differenciating it w.r.t. x, we get
-3dx = dt
dx =-1/3 dt
integral 7*(-1/3)/t dt
= -7/3 log t
put t= 2-3x
we get
-7/3 log (2-3x )