integration cosec ^2/1+cot x dx
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Answer:
Explanation:12log∣∣∣1+cotx1−cotx∣∣∣+C
−12log∣∣∣1+cotx1−cotx∣∣∣+C
12log∣∣∣1−cotx1+cotx∣∣∣+C
None of these
Answer :
B
Solution :
Put cotx=tand−cosec2xdx=dt.
∴I=−∫dt(1−t2)=−1(2×1)log∣∣∣1+t1−t∣∣∣+C=−12log∣∣∣1+cotx1−cotx∣∣∣+C
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Answer:
Solution : Put cotx=tand-cosec2xdx =dt. ∴I=-∫dt(1-t2)=-1(2×1)log|1+t1-t|+C=-12 log|1+cotx1-cotx|+C. Related Videos.
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