Question

integration dx/(2x+2)².upper limit=2,lower limit=1​

Answer 1

Answer:

₁²∫(2x+2)²dx

=> ₁²∫ 4x² + 8x + 4 dx

=> ₁²∫4x² dx + ₁²∫8x dx + ₁²∫4 dx

=> [4/3x³ + 8/2x² + 4x ]

=> [4/3x³ + 4x² + 4x]₁²

=> [{4/3 (2)³+4(2)²+4(2)} - {4/3(1)³+4(1)²+4(1)}]

=> [{4/3*8 + 4*4 + 8} - {4/3 + 4 + 4}]

=> (32/3 + 24) - (4/3+8)

=> (32 + 72)/3 - (4 + 24)/3

=> 104/3 - 28/3

=> (104 - 28)/3

=> 76/3

=> 25¹/₃