integration DX by 1 minus sin x
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dx/(1-sinx)
put sinx= (2tan(x/2))/(1+(tan(x/2))^2)
put sinx= (2tan(x/2))/(1+(tan(x/2))^2)
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manu250301:
we can do it in a much simpler way
yup
multiply the term by
by rationalizing
yes
but questions of this form can always be integrated by the method i just wrote. rationalising the term wont work everytime
i just provided the general solution!
COOL....
Answered by
0
Answer:
Step-by-step explanation:
firrst rationalize it by multiplying and dividing by( 1+ sin x).
after rationalization it will become ⇒
∫(1+sinx/cos²x )dx
then ⇒∫1/cos²x dx + ∫sinx/ cos²x dx
⇒(∫sec²x + ∫tanx secx )dx
= tanx +secx+ c
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