Question

integration dx\secx+tanx​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

log |1+sinx | +c

Step-by-step explanation:

Integration dx/(secx+tanx) = integration (cosx/1+sinx)

Let, 1+sinx =t

On differentiating with respect to x, we get

cosxdx = dt

Then,

Integration dx(cosx/1+sinx) = integration (dt/t)

= log |t| + c

= log | 1 + sinx | + c