Question

Integration e power logx base e upon x dx

Answer 1

Answer:

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Step-by-step explanation:

Let’s assume you mean the logarithm to base b:

elogbx=elnxlnb=x1lnb

Integrating:

∫x1lnbdx=11lnb+1x1lnb+1+C=lnblnb+1x1lnb+1+C

If b=e, then the result is  12x2+C