Question

Integration hai hai solve it fast

Answer 1

question 1.

e^log power x base e = x
then integration of x = x square/,2

question 2.



sec2x−1=tan2xsec2⁡x−1=tan2⁡x

∫tan2xdx=∫sec2x−1dx∫tan2⁡xdx=∫sec2⁡x−1dx

Using the Sum Rule:

∫sec2x−1dx=∫sec2xdx−∫dx∫sec2⁡x−1dx=∫sec2⁡xdx−∫dx

Use the standard integral: ∫sec2xdx=tanx+C∫sec2⁡xdx=tan⁡x+C

Therefore the integral is

∫tan2xdx=tanx−x+C