Question

integration
log x dx/x
​

Answer 1

Answer:

according to me..........

Answer 2

Answer:

logx^2/2+c

Step-by-step explanation:

logxdx/x

let logx=t

dx/x=DT

integration of (tdt)

= t^2/2+c

since t=logx

so logx^2/2+c

hope you are satisfied with my answer