integration log x/x dx
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Put logx=t
differentiating wrt to x
1/x =dt/dx
dt=dx/x
now replacing all values
we get
integration of t
which is
t^2/2
resubstitute t as logx
therefore
(logx)^2/2
Hope it helps
Tap the blue crown
differentiating wrt to x
1/x =dt/dx
dt=dx/x
now replacing all values
we get
integration of t
which is
t^2/2
resubstitute t as logx
therefore
(logx)^2/2
Hope it helps
Tap the blue crown
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