Question

integration of 1/(2x+3) dx​

Answer 1

Answer:

ln((2x+3)^1/2)

Explanation:

start by putting 2x+3=t

by differentiating 2x+3=t w.r.t x

we get 2=dt/dx

now dt=2dx

now the expression 1/(2x+3) dx can be written as 1/2(2dx/(2x+3))

now by putting 2dx=t

integral 1/2(dt/t)= 1/2ln(2x+3)=ln((2x+3)^1/2)