Question

integration of 1 by root 16-x2​

Answer 1

Answer:

=sin−1(14x)+C. Explanation: ∫1√16−x2dx. ∫1√16(1−x216)dx. ∫14√1−(x4)2dx. 14∫1√1−(x4)2dx. Let u=14x dudx=14 4du=dx.

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