Integration of 1 / cot X + tan x dx pllz answer
Answers
Answered by
0
on simplifying we obtain it as
tanx/1+tan^2x
=sinx cosx
=(sin2x)/2
integerating it we obtain
(-cos2x/4)
tanx/1+tan^2x
=sinx cosx
=(sin2x)/2
integerating it we obtain
(-cos2x/4)
Answered by
0
that's the answer for your question
Attachments:
Similar questions