Question

integration of {1/log x -1/ (log x)^2 }dx

Answer 1

Answer:

plzz give me brainliest ans and plzzzz follow me please

Answer 2

Answer:

Answer:

your question is ->

you can easily solve this question with help of substitution method

put x = tanθ

differentiating both sides,

dx = sec²θ dθ

now limits : upper limits = 1 = tanθ ⇒θ = π/4 and lower limits = 0 = tanθ ⇒θ = 0°

now,

I =

I = .....(1)

we know,

so,

we know, tan(π/4- θ) = (1 - tanθ)/(1 + tanθ)

so, I =

=

= ......(2)

adding equations (1) and (2),

we get, 2I =

Step-by-step explanation: