Question

Integration of 1/sin^2x

Answer 1

Step-by-step explanation:

We know that sin^2 x + cos^2 x = 1 and sin 2x = 2sinxcosx

So integ.√(1+sin 2x)dx

=Integ.√(sin^2 x + cos^2 x + 2sinx cosx)dx

= integ.√(sin x + cos x)^2 dx

=Integ.(sin x + cos x)dx

-cosx+sin x + c

HOPE IT HELPS!!

Answer 2

Integration of 1/sin^2x = Integration of cosec^2x (As per trigonometry)

Integration of cosec^2x = -log(cosecx + cotx) + c