Question

integration of 1/x^2​

Answer 1

⭐《ANSWER》

$\huge\mathfrak{\underline {\underline\pink {ANSWER}}}$

↪Actually welcome to the concept of the INTEGRATION ,

↪Basically here , we can write , 1/x^2 as x^-2

↪Now , we know that ,

↪Integration of x^n dx = x^n+1 / n+1

↪So applying here , we get as,

↪Integration of x^-2 dx = x^-2+1 / -2+1

↪so we get as ,

↪Integration of x^-2 dx = x^-1 /-1 + C

〽==》 integration x^-2 dx = -1/ x + C

↪So here ,

⭐I = -1/x + C

↪where , C is the Integration Constant

Answer 2

$Hey Guys here is your answer$

$1/x^2$

$-1/X+c$

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