Question

integration of 1/x^3 is​

Answer 1

Answer:

$-\frac{1}{2x^{2} } +C$

Step-by-step explanation:

We know that $\frac{1}{a^b} =a^{-b}$

⇒ $\int\frac{1}{x^3}dx$ = $\int x^{-3}dx$

We know that $\int x^ndx = \frac{x^{n+1}}{n+1}$

⇒$\int x^{-3}dx=\frac{x^{-3+1}}{-3+1} =\frac{x^{-2}}{-2} =-\frac{1}{2x^2}=\frac{1}{2x^2}+C$             Answer