Question

Integration of 1/(x²+a²)²

Answer 1

Answer:

ed with Mathematica by typing:

Integrate[1/(x^2 + a^2)^n, x]

The solution obtained is:

∫1(a2+x2)ndx=x(a2+x2)−n(x2a2+1)n2F1(12,n;32;−x2a2)+C

The special function 2F1(a,b;c;z