Question

integration of 2sinx/1+cos2x

Answer 1

➡HERE IS YOUR ANSWER⬇

$\frac{2sinx}{1 + cos2x} \\ \\ = \frac{2sinx}{1 + (2 {cos}^{2} x - 1)} \\ \\ = \frac{2sinx}{2 {cos}^{2} x} \\ \\ = \frac{sinx}{cosx} \frac{1}{cosx} \\ \\ = tanx \: secx \\ \\ = secx \: tanx$

Now,

integration of [secx tanx dx]

= secx + c, where c is integral constant.

Formula is :

integration of [secx tanx dx]

= secx + c, where c in integral constant.

⬆HOPE THIS HELPS YOU⬅