Question

integration of (2t - 4)^-4 dt:​

Answer 1

Answer:

$∫ {(2t - 4)}^{ - 4} dx \\ \\ integrate \: w \: .r \:. t \:. x \\ \\ \frac{ {(2t - 4)}^{ - 4 + 1} }{ (- 4 + 1)2} + c \\ \\ \frac{ {(2t - 4)}^{ - 3} }{( - 3)(2)} + c \\ \\ \frac{ ({2t - 4)}^{ - 3} }{ - 6 } + c \\ \\ - \frac{ 1 {(2t - 4)}^{3} }{6} + c$