integration of 2t+5/-t-2 is
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Answered by
0
Answer:
Step-by-step explanation:
I will use the following properties:
d
d
t
t
n
=
n
t
n
−
1
if
n
≠
0
∫
(
d
d
t
f
(
t
)
)
d
t
=
f
(
t
)
+
C
where
C
is a constant
∫
(
f
(
t
)
+
g
(
t
)
)
d
t
=
∫
f
(
t
)
d
t
+
∫
g
(
t
)
d
t
∫
k
f
(
t
)
d
t
=
k
∫
f
(
t
)
d
t
From the first two properties, we can deduce that if
n
≠
−
1
that:
∫
t
n
d
t
=
1
n
+
1
t
n
+
1
+
C
The third and fourth properties tell us that integration is a linear operator.
We can deduce that:
∫
(
3
t
2
+
2
t
+
2
)
d
t
=
3
∫
t
2
d
t
+
2
∫
t
d
t
+
2
∫
1
d
t
∫
(
3
t
2
+
2
t
+
2
)
d
t
=
t
3
+
t
2
+
2
t
+
C
where
C
is a constant.
Answered by
1
Answer:
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