Integration of 2v/(1-v)
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v^2/1-v is the answer
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Integration of 2v / (1-v) is 2( 1 – v ) – 2 ln ( 1 -v )
- We have to calculate∫▒〖2v dv/(1-v)〗 ……..(i)
- let (1-v) = t
differentiating both sides ,
-dv = dt ……………..(ii)
- putting value from (ii) to (i) and after manipulation,
∫▒〖2(t-1)dt/t〗 = ∫▒〖2 dt〗 - ∫▒〖2 dt/t〗
= 2t – 2 ln t
- putting t = 1-v we get,
2(1-v) – 2 ln (1-v)
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