Question

Integration of√2x^2-x+1 dx

Answer 1

Answer:

Let u = 1 + 2x^2

du = 4x dx

dx = du/4x

∫(x√1+2x^2)dx = ∫x * u^1/2*du/4x

= ∫u^1/2/4 du

= 1/4∫u^1/2 du

= 1/4 ( 2/3 u^3/2) + C

= 1/6 (1 + 2x^2)^3/2 + C

Answer 2

Step-by-step explanation:

• See the above attachment..