Question

integration of 2x cube minus 3 X + 5 by 2 x square into DX ​

Answer 1

Answer:

0 to 1......( only the denominator is in square root) ... (3x^3-x^2+ 2x-4)/(x^2-3x+2)^0.5 from 0 to 1. ... 5) Now comes second part, I(2) Now, (x - 1) = c \times \frac{d}{dx

Q: Integrate from 0 to 1 : $\frac{3 {x}^{3} - {x}^{2} + 2x - 4}{ \sqrt{ {x}^{2} - 3x + 2} }$Final Answer : [tex] \frac{1}{16} ( - 202 \sqrt{2} ...