Question

integration of 2x dx/3√(x²+1)

Answer 1

2xdx/(3√(x²+1)
Let z= √(x²+1)
dz = 2xdx/√(x²+1)×(1/2) 
     = xdx/√(x²+1)
2dz = 2xdx/√(x²+1)
substituting this value
now integration of (2/3)dz
= (2/3)z 
=(2/3)√(x²+1)

Answer 2

Step-by-step explanation:

• See the attachment.......