integration of 2x dx/3√(x²+1)
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2xdx/(3√(x²+1)
Let z= √(x²+1)
dz = 2xdx/√(x²+1)×(1/2)
= xdx/√(x²+1)
2dz = 2xdx/√(x²+1)
substituting this value
now integration of (2/3)dz
= (2/3)z
=(2/3)√(x²+1)
Let z= √(x²+1)
dz = 2xdx/√(x²+1)×(1/2)
= xdx/√(x²+1)
2dz = 2xdx/√(x²+1)
substituting this value
now integration of (2/3)dz
= (2/3)z
=(2/3)√(x²+1)
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