Question

integration of 3/2 under root x In physics

Answer 1

$i = int. \frac{3}{2} \sqrt{x } \\ = \frac{3}{2} \times \frac{ {x}^{ \frac{3}{2} + 1 } }{ \frac{3}{2} + 1} \\ = \frac{3}{2} \times \frac{ {x}^{ \frac{5}{2} } }{ \frac{5}{2} } \\ = \frac{3}{5} \times {x}^{ \frac{5}{2} }$
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Answer 2

Answer:

its answer is root x raise to power 3 =

$\sqrt{x}^{3}$

Step-by-step explanation:

$\sqrt{x ^{3} }$