integration of 3/(2-x)^2 dx
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Answer:
3/(2-x) + c
Explanation:
We can use the following substitution:
u = 2 - x --------------------------> 1
=> du = -dx ----------------------> 2
Now substitute 1 and 2 above in our integral. 3 being a constant will come out of the integral and you need to integrate - (1/(u^2)).
The answer is 1/u = 1/(2-x)
The final answer = 3/(2-x) + c
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