integration of 3x-1/(x-2)^2
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Answer:
3X-1/(X+2)^2=A/X+2 +B/(X+2)^2
solution
3X-1=A(X+2)+B
3X-1=AX+2A+B
AS YOU CAN SEE
A=3
2A+B=-1
B=-1-6
B=-7
find int
∫3X-1/(X+2)²=³∫dX/X+2 -7∫dx/(x+2)²
x+2=t
dx=dt
³∫dt/t −7∫t-²dt
3ln t-7[t^-1/-1]+c
3lnt+7/t+c
3ln(x+2)+ 7/x+2 +c
Step-by-step explanation:
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