Math, asked by surajchadri, 1 year ago

integration of 3x-1/(x-2)^2

Answers

Answered by NIMISHGUPTA
27
i think this may help you
Attachments:
Answered by jitekumar4201
6

Answer:

3X-1/(X+2)^2=A/X+2 +B/(X+2)^2

solution

3X-1=A(X+2)+B

3X-1=AX+2A+B        

AS YOU CAN SEE

A=3  

2A+B=-1

B=-1-6

B=-7

find int

∫3X-1/(X+2)²=³∫dX/X+2 -7∫dx/(x+2)²

x+2=t

dx=dt

³∫dt/t  −7∫t-²dt

3ln t-7[t^-1/-1]+c

3lnt+7/t+c

3ln(x+2)+ 7/x+2  +c

Step-by-step explanation:

Similar questions