integration of 3x^2+2x+1) dx = 11
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- [ 3x^2/3+2x/2+x] / a1 =11
=x^2+x2+x /a2=11
=(a^2-1)+(a2-1)+(a-1)=11
=(a^2+a2+a)-3=11
=a^2+a2+a-14=0
=(a-2). (a2+3a+7)=0
=a-2=0 (or) a2+3a+7=0
answer is =a=2
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