Question

integration of 3x / under root x^2+4 dx​

Answer 1

Answer:

,

Explanation:

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Answer 2

Answer:

$3( \sqrt{ {x}^{2} + 4 } )$

Explanation:

integration of 3x / under root x^2+4 dx

let us assume x^2+4=t^2

by differentiating we get xdx = tdt

integration of 3 tdt/t

integration of 3dt

=3t

where

$t = \sqrt{ {x}^{2} + 4 }$

so the answer is

$3( \sqrt{ {x}^{2} + 4 } )$