CBSE BOARD XII, asked by sonwanesakshi, 1 month ago

integration of 3x / under root x^2+4 dx​

Answers

Answered by quamrulhoda001
0

Answer:

,

Explanation:

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Answered by pragnasrimiddela
0

Answer:

3( \sqrt{ {x}^{2} + 4 } )

Explanation:

integration of 3x / under root x^2+4 dx

let us assume x^2+4=t^2

by differentiating we get xdx = tdt

integration of 3 tdt/t

integration of 3dt

=3t

where

t =  \sqrt{ {x}^{2} + 4 }

so the answer is

3( \sqrt{ {x}^{2} + 4 } )

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