Question

Integration of 4 + 2 t limit 2 and 6

Answer 1

Answer:

Explanation:

$\int\limits^6_2 {4 + 2t} \, dt$

[4t + 2t²/2]⁶₂

[4t + t²]⁶₂

(4 × 6 + 6²) - ( 4 × 2 + 2²)

24 +36 - 8 - 4

60 - 12

48