Physics, asked by bhavyadiwedi2906, 7 months ago

integration of (4-3x)^5.dx​

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Answered by Anonymous
3

\sf \int (4-3x)^5 \:dx \\\\\sf</p><p>Let \:4-3x \:be \:m\\\\\sf</p><p>Then, \int m^5 .dx= \frac{m^{5+1}}{5+1} \:+\: C\\\\\sf</p><p>=\frac{m^{6}}{6} \:+\: C\\\\\sf</p><p>=\frac{(4-3x)^6}{6}\:+\: C\\\\\sf</p><p>

Answered by Anonymous
1

refer attachment.

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