integration of 4+√x divide by t^3
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£4/x3dx+£√x/x³dx
=£4x^-3dx+£x^1/2-3dx
=4x^(-3-1)/(-3-1)+x^-5/2-1/(-5/2-1)
4x^-4/-4+x^-7/2/-7/2
=-x^-4-2/7x^-7/2+c
=£4x^-3dx+£x^1/2-3dx
=4x^(-3-1)/(-3-1)+x^-5/2-1/(-5/2-1)
4x^-4/-4+x^-7/2/-7/2
=-x^-4-2/7x^-7/2+c
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