Math, asked by sameersammy5678, 7 months ago

integration of (4x+3)dx/(2x^2+3x+1)^4

Answers

Answered by somalanaikmudavath56

0

Answer:

2√2x^2+3x+1+c

Step-by-step explanation:

(4x+3)dx/(2x^2+3x+1)^4

d/DX(2x^2+3x+1)=4x+3

4x+3/√2x^2+3x+1. DX=1)(2x^2+3x+1)^-1/2 +1+c

2(2x^2+3x+1)+c

= 2√2x^2+3x+1 +c

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