Math, asked by mjarushi6335, 9 days ago

integration of 5cosx - 3sinx + 2/cos²x

Answers

Answered by donna17

Step-by-step explanation:

5cosx - 3sinx + 2/cos2x)dx = 5∫cosxdx - 3∫sinxdx + 2∫sec2xdx = 5sinx - 3(-cosx) + 2tanx + c = 5sinx + 3cosx + 2tanx + cRead more on Sarthaks.com - https://www.sarthaks.com/711996/find-the-value-of-the-integrates-given-below-5cosx-3sinx-2-cos-2x-dx

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