Integration of 5x+1 / (x-2)(x-3) dx
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Answer:
Step-by-step explanation:
f
(
x
)
=
5
∫
x
(
x
−
2
)
1
2
d
x
Let's
u
=
x
−
2
d
u
=
1
x
=
u
+
2
Now we have :
=
5
∫
u
+
2
u
1
2
d
u
=
5
∫
√
u
d
u
+
10
∫
1
√
u
d
u
=
[
10
3
√
u
3
]
+
20
[
√
u
]
+
C
Substitute back
10
3
(
x
−
2
)
3
2
+
20
(
x
−
2
)
1
2
+
C
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