integration of (a/x^2+b/x) DX and a and b are constant
Answers
Answered by
22
Explanation:
Take in mind a & b are constants and thereby integrate a/x^2 and b/x individually
=>integral of (a/x^2) dx + integral of (b/x) dx
=> a (integral of x^-2)dx + b(integral of 1/x) dx
=> a (x^-1)/ -1 + b log | x | + c
=> b log|x| - (a/x) + c
Answered by
14
Explanation:
this is surely correct plz thank the answer
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