Question

integration of alphadt​

Answer 1

Answer:

α t + C

Step-by-step explanation:

To find---> ∫ α dt

Solution---> We have to find intregation of α with respect to t,so α is cosidered as constant

Now we know that

∫ 1 dt = t + C

Now, returning to original problem,

∫ α dt = α ∫ 1 dt

= α t + C

Additional information---->

1) ∫ xⁿ dx = xⁿ⁺¹ / ( n + 1 ) + C

2) ∫ eˣ dx = eˣ + C

3) ∫ aˣ dx = aˣ / loga + C

4) ∫ Sinx dx = -Cosx + C

5) ∫ Cosx dx = Sinx + C

6) ∫ Sec²x dx = tanx + C

7) ∫ Cosec²x dx = -Cotx + C

8) ∫ Cosecx Cotx dx = - Cosecx + C

9) ∫ Secx tanx dx = Secx + C

Answer 2

Answer:

Step-by-step explanation:

∫ α dt

∫ 1 dt = t + C

∫ α dt = α ∫ 1 dt

= α t + C