Question

integration of b^(x+a)​

Answer 1

Answer:

Hello Rashmi

Here is your answer :-

I = {b^(x+a)}/ log(b)

Thank you!!

Step-by-step explanation:

As , we know that in derivative we generally multiplying for finding differential of exponential expression.

i.e. derivative of 2^x = 2^x log (2)

similarly, in integral we dividing

i.e. Integral of 2^x = 2^x / log 2

so, here b is a constant at the place of 2 .

Hope you understand! !

Thank you! !