integration of b^(x+a)
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Answer:
Hello Rashmi
Here is your answer :-
I = {b^(x+a)}/ log(b)
Thank you!!
Step-by-step explanation:
As , we know that in derivative we generally multiplying for finding differential of exponential expression.
i.e. derivative of 2^x = 2^x log (2)
similarly, in integral we dividing
i.e. Integral of 2^x = 2^x / log 2
so, here b is a constant at the place of 2 .
Hope you understand! !
Thank you! !
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