Question

Integration of Cos 3 x + sin x dx​

Answer 1

Answer:

$\frac{sin3x}{3} - cosx+ c \:$

Step-by-step explanation:

$integration \: of \: ( \:cos3x + sinx )dx \\ = \frac{sin3x}{3} + (- cosx)+ c \\ = \frac{sin3x}{3} - cosx+ c$

Answer 2

Here ,

I = integration (cos 3x + sin x)dx

I = [(sin 3x /3) + (-cosx)] + C

{ because

integration (cos ax) = sinax/a

&

integration (sin x) = (-cos x) }

I = (sin 3x / 3) - (cos x) + C