Question

integration of cos2x / sin2x

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Answer 1

Answer:

We have to find the integral of y = (cos x)^2 - (sin x)^2.

We know that cos 2x = (cos x)^2 - (sin x)^2

⇒ y = cos 2x

Integration [ cos 2x dx]

let 2x = y, dy/2 = dx

⇒ Integration [(1/2)cos y dy]

⇒ (1/2) sin y + C

substitute y = 2x

⇒ (1/2)*sin 2x + C

The required integral is (1/2)*sin 2x + C

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